RRB NTPC Graduation 2025 Profit and Loss 01

 🧮 RRB NTPC Maths Question with Solution

1)Yashika buys 6 apples and 6 mangoes for ₹216. When the cost of an apple is decreased by 30% and that of a mango remains the same, then the cost of 5 apples and 8 mangoes is ₹162. What is the original cost of 7 apples and 2 mangoes?

ಯಾಶಿಕಾ 6 ಸೇಬು ಮತ್ತು 6 ಮಾವಿನ ಹಣ್ಣುಗಳನ್ನು ₹216 ಕ್ಕೆ ಖರೀದಿಸುತ್ತಾಳೆ. ಒಂದು ಸೇಬಿನ ಬೆಲೆಯಲ್ಲಿ 30% ರಷ್ಟು ಇಳಿಕೆಯಾಗಿ ಮಾವಿನ ಬೆಲೆ ಹಾಗೆಯೇ ಉಳಿದರೆ, 5 ಸೇಬು ಮತ್ತು 8 ಮಾವಿನ ಹಣ್ಣುಗಳ ಬೆಲೆ ₹162 ಆಗುತ್ತದೆ. 7 ಸೇಬು ಮತ್ತು 2 ಮಾವಿನ ಹಣ್ಣುಗಳ ಮೂಲ ಬೆಲೆ ಎಷ್ಟು?

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✏️ Solution:

Let the original cost of:

• 1 apple = ₹A

• 1 mango = ₹M

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✅ Step 1: Form the First Equation

6 apples + 6 mangoes = ₹216

6A + 6M = 216

Divide both sides by 6:

A + M = 36 → (Equation 1)

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✅ Step 2: Form the Second Equation

Apple price decreased by 30%

New apple price = 70% of A
= 0.7A

According to the question:

5 apples + 8 mangoes = ₹162

5(0.7A) + 8M = 162

3.5A + 8M = 162 → (Equation 2)

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✅ Step 3: Solve the Equations

From Equation 1:

A = 36 − M

Substitute in Equation 2:

3.5(36 − M) + 8M = 162

126 − 3.5M + 8M = 162

126 + 4.5M = 162

4.5M = 36

M = 8

Now substitute in Equation 1:

A + 8 = 36

A = 28

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✅ Step 4: Find Required Value

Original cost of 7 apples and 2 mangoes:

7A + 2M
= 7(28) + 2(8)
= 196 + 16
= ₹212

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🎯 Final Answer: ₹212

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2)ಗೌರವ್ ಮೊದಲ ಪೆನ್ನು ₹444 ಕ್ಕೆ ಮತ್ತು ಎರಡನೇ ಪೆನ್ನು ₹356 ಕ್ಕೆ ಖರೀದಿಸಿದರು. ಅವರು ಮೊದಲ ಪೆನ್ನು ಲಾಭದ 75% ಗೆ ಮಾರಾಟ ಮಾಡುತ್ತಾರೆ ಆದರೆ ಖರೀದಿದಾರ ಬೆಲೆಗೆ ಚೌಕಾಶಿ ಮಾಡುತ್ತಾರೆ, ಮತ್ತು ಅವರು 14% ರಿಯಾಯಿತಿಯನ್ನು ಮತ್ತು ಎರಡನೇ ಪೆನ್ನು ಲಾಭದ 48% ಗೆ ನೀಡಬೇಕಾಗುತ್ತದೆ. ಈ ವಹಿವಾಟಿನಲ್ಲಿ ಅವರು ಪಡೆದ ಒಟ್ಟು ಲಾಭವನ್ನು ಕಂಡುಹಿಡಿಯಿರಿ (ಎರಡು ದಶಮಾಂಶ ಸ್ಥಾನಗಳಿಗೆ ಸರಿಯಾಗಿ).

Gaurav bought the first pen for ₹444 and the second pen for ₹356, respectively. He sells the first pen at 75% of the profit but the buyer bargains for the price, and he has to offer a 14% discount and the second pen at 48% of the profit. Find the total profit he had in this transaction (correct to two decimal places).

A) ₹396.11 

B) ₹399.02 

C) ₹394.67 

D) ₹395.10 

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🟢 Given:

Cost price (CP) of first pen = ₹444
Cost price (CP) of second pen = ₹356

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✏️ First Pen

He sells at 75% profit

Step 1: Calculate Marked Price (MP)

Profit = 75% of 444

= 0.75 × 444
= 333

Marked Price = 444 + 333
= ₹777

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Step 2: 14% Discount on MP

Discount = 14% of 777

= 0.14 × 777
= 108.78

Selling Price (SP₁) = 777 − 108.78
= ₹668.22

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Step 3: Profit on First Pen

Profit₁ = 668.22 − 444
= ₹224.22

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✏️ Second Pen

Sold at 48% profit

Profit = 48% of 356

= 0.48 × 356
= 170.88

Selling Price (SP₂) = 356 + 170.88
= ₹526.88

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Profit on Second Pen

Profit₂ = ₹170.88

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✅ Total Profit

Total Profit = 224.22 + 170.88

= ₹395.10

🎯 Correct Answer: D) ₹395.10

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3)ಗೋವಿಂದ್ ಒಟ್ಟು ₹4,800 ಬೆಲೆಗೆ ಎರಡು ವಸ್ತುಗಳನ್ನು ಖರೀದಿಸಿದರು. ಅವರು ಒಂದು ವಸ್ತುವನ್ನು 34% ಲಾಭಕ್ಕೆ ಮತ್ತು ಇನ್ನೊಂದು ವಸ್ತುವನ್ನು 10% ನಷ್ಟಕ್ಕೆ ಮಾರಿದರು.ಗೋವಿಂದರು ಎರಡೂ ವಸ್ತುಗಳನ್ನು ಒಟ್ಟಿಗೆ ₹5,442 ಕ್ಕೆ ಮಾರಾಟ ಮಾಡಿದರೆ, ಎರಡೂ ವಸ್ತುಗಳ ವೆಚ್ಚದ ಬೆಲೆ (₹ ನಲ್ಲಿ) ನಡುವಿನ ವ್ಯತ್ಯಾಸವೇನು?

Govind bought two items at a total cost of ₹4,800. He sold one item at 34% profit and the other at 10% loss. If

Govind sold both the items together for ₹5,442, then what is the difference between the cost price (in ₹) of both

the items?

ಎ) 350

ಬಿ) 300

ಸಿ) 275

ಡಿ) 325

17/06/2025 ಶಿಫ್ಟ್ -2

Let’s solve it step-by-step.

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🟢 Given:

Total Cost Price (CP) of two items = ₹4800
Total Selling Price (SP) = ₹5442

One item sold at 34% profit
Other item sold at 10% loss

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✏️ Step 1: Assume

Let CP of first item = ₹x
Then CP of second item = ₹(4800 − x)

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✏️ Step 2: Form Selling Price equation

First item sold at 34% profit:

SP₁ = 1.34x

Second item sold at 10% loss:

SP₂ = 0.90(4800 − x)

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Total SP:

1.34x + 0.90(4800 − x) = 5442

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✏️ Step 3: Solve equation

1.34x + 4320 − 0.90x = 5442

0.44x + 4320 = 5442

0.44x = 1122

x = 1122 / 0.44

x = 2550

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✏️ Step 4: Find other CP

Second item CP = 4800 − 2550

= 2250

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✏️ Step 5: Find Difference

Difference = 2550 − 2250

= ₹300

🎯 Correct Answer: B) ₹300

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4)If the selling price of a bed is 2-times of initial, then the profit is 8-times of initial. Find the initial profit percentage(in %).

ಹಾಸಿಗೆಯ ಮಾರಾಟದ ಬೆಲೆ ಆರಂಭಿಕ ಬೆಲೆಯ 2 ಪಟ್ಟು ಇದ್ದರೆ, ಲಾಭವು ಆರಂಭಿಕ ಬೆಲೆಯ 8 ಪಟ್ಟು ಇರುತ್ತದೆ. ಆರಂಭಿಕ ಲಾಭದ ಶೇಕಡಾವಾರು ಪ್ರಮಾಣವನ್ನು (% ನಲ್ಲಿ) ಕಂಡುಹಿಡಿಯಿರಿ.

ಎ) 300

ಬಿ) 400

ಸಿ) 25

ಡಿ) 16.67

19/06/2025 ಶಿಫ್ಟ್-3

Let’s solve it clearly step-by-step.

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🟢 Assume

Let initial cost price (CP) = ₹x

Let initial profit = ₹p

So,

Initial Selling Price (SP₁) = x + p

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🟢 According to Question

New Selling Price (SP₂) = 2 × (initial SP)
= 2(x + p)

New Profit = 8 × (initial profit)
= 8p

But,

New Profit = SP₂ − CP

So,

2(x + p) − x = 8p

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🟢 Solve the Equation

2x + 2p − x = 8p

x + 2p = 8p

x = 6p

So,

p = x / 6

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🟢 Find Initial Profit %

Initial Profit % = (Profit / CP) × 100

= (x/6 ÷ x) × 100

= (1/6) × 100

= 16.67%

🎯 Correct Answer: D) 16.67%

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