🧮 RRB NTPC Maths Question with Solution
1)Yashika buys 6 apples and 6 mangoes for ₹216. When the cost of an apple is decreased by 30% and that of a mango remains the same, then the cost of 5 apples and 8 mangoes is ₹162. What is the original cost of 7 apples and 2 mangoes?
ಯಾಶಿಕಾ 6 ಸೇಬು ಮತ್ತು 6 ಮಾವಿನ ಹಣ್ಣುಗಳನ್ನು ₹216 ಕ್ಕೆ ಖರೀದಿಸುತ್ತಾಳೆ. ಒಂದು ಸೇಬಿನ ಬೆಲೆಯಲ್ಲಿ 30% ರಷ್ಟು ಇಳಿಕೆಯಾಗಿ ಮಾವಿನ ಬೆಲೆ ಹಾಗೆಯೇ ಉಳಿದರೆ, 5 ಸೇಬು ಮತ್ತು 8 ಮಾವಿನ ಹಣ್ಣುಗಳ ಬೆಲೆ ₹162 ಆಗುತ್ತದೆ. 7 ಸೇಬು ಮತ್ತು 2 ಮಾವಿನ ಹಣ್ಣುಗಳ ಮೂಲ ಬೆಲೆ ಎಷ್ಟು?
✏️ Solution:
Let the original cost of:
1 apple = ₹A
1 mango = ₹M
✅ Step 1: Form the First Equation
6 apples + 6 mangoes = ₹216
6A + 6M = 216
Divide both sides by 6:
A + M = 36 → (Equation 1)
✅ Step 2: Form the Second Equation
Apple price decreased by 30%
New apple price = 70% of A
= 0.7A
According to the question:
5 apples + 8 mangoes = ₹162
5(0.7A) + 8M = 162
3.5A + 8M = 162 → (Equation 2)
✅ Step 3: Solve the Equations
From Equation 1:
A = 36 − M
Substitute in Equation 2:
3.5(36 − M) + 8M = 162
126 − 3.5M + 8M = 162
126 + 4.5M = 162
4.5M = 36
M = 8
Now substitute in Equation 1:
A + 8 = 36
A = 28
✅ Step 4: Find Required Value
Original cost of 7 apples and 2 mangoes:
7A + 2M
= 7(28) + 2(8)
= 196 + 16
= ₹212
🎯 Final Answer: ₹212
2)ಗೌರವ್ ಮೊದಲ ಪೆನ್ನು ₹444 ಕ್ಕೆ ಮತ್ತು ಎರಡನೇ ಪೆನ್ನು ₹356 ಕ್ಕೆ ಖರೀದಿಸಿದರು. ಅವರು ಮೊದಲ ಪೆನ್ನು ಲಾಭದ 75% ಗೆ ಮಾರಾಟ ಮಾಡುತ್ತಾರೆ ಆದರೆ ಖರೀದಿದಾರ ಬೆಲೆಗೆ ಚೌಕಾಶಿ ಮಾಡುತ್ತಾರೆ, ಮತ್ತು ಅವರು 14% ರಿಯಾಯಿತಿಯನ್ನು ಮತ್ತು ಎರಡನೇ ಪೆನ್ನು ಲಾಭದ 48% ಗೆ ನೀಡಬೇಕಾಗುತ್ತದೆ. ಈ ವಹಿವಾಟಿನಲ್ಲಿ ಅವರು ಪಡೆದ ಒಟ್ಟು ಲಾಭವನ್ನು ಕಂಡುಹಿಡಿಯಿರಿ (ಎರಡು ದಶಮಾಂಶ ಸ್ಥಾನಗಳಿಗೆ ಸರಿಯಾಗಿ).
Gaurav bought the first pen for ₹444 and the second pen for ₹356, respectively. He sells the first pen at 75% of the profit but the buyer bargains for the price, and he has to offer a 14% discount and the second pen at 48% of the profit. Find the total profit he had in this transaction (correct to two decimal places).
A) ₹396.11
B) ₹399.02
C) ₹394.67
D) ₹395.10
🟢 Given:
Cost price (CP) of first pen = ₹444
Cost price (CP) of second pen = ₹356
✏️ First Pen
He sells at 75% profit
Step 1: Calculate Marked Price (MP)
Profit = 75% of 444
= 0.75 × 444
= 333
Marked Price = 444 + 333
= ₹777
Step 2: 14% Discount on MP
Discount = 14% of 777
= 0.14 × 777
= 108.78
Selling Price (SP₁) = 777 − 108.78
= ₹668.22
Step 3: Profit on First Pen
Profit₁ = 668.22 − 444
= ₹224.22
✏️ Second Pen
Sold at 48% profit
Profit = 48% of 356
= 0.48 × 356
= 170.88
Selling Price (SP₂) = 356 + 170.88
= ₹526.88
Profit on Second Pen
Profit₂ = ₹170.88
✅ Total Profit
Total Profit = 224.22 + 170.88
= ₹395.10
🎯 Correct Answer: D) ₹395.10
3)ಗೋವಿಂದ್ ಒಟ್ಟು ₹4,800 ಬೆಲೆಗೆ ಎರಡು ವಸ್ತುಗಳನ್ನು ಖರೀದಿಸಿದರು. ಅವರು ಒಂದು ವಸ್ತುವನ್ನು 34% ಲಾಭಕ್ಕೆ ಮತ್ತು ಇನ್ನೊಂದು ವಸ್ತುವನ್ನು 10% ನಷ್ಟಕ್ಕೆ ಮಾರಿದರು.ಗೋವಿಂದರು ಎರಡೂ ವಸ್ತುಗಳನ್ನು ಒಟ್ಟಿಗೆ ₹5,442 ಕ್ಕೆ ಮಾರಾಟ ಮಾಡಿದರೆ, ಎರಡೂ ವಸ್ತುಗಳ ವೆಚ್ಚದ ಬೆಲೆ (₹ ನಲ್ಲಿ) ನಡುವಿನ ವ್ಯತ್ಯಾಸವೇನು?
Let’s solve it step-by-step.
🟢 Given:
Total Cost Price (CP) of two items = ₹4800
Total Selling Price (SP) = ₹5442
One item sold at 34% profit
Other item sold at 10% loss
✏️ Step 1: Assume
Let CP of first item = ₹x
Then CP of second item = ₹(4800 − x)
✏️ Step 2: Form Selling Price equation
First item sold at 34% profit:
SP₁ = 1.34x
Second item sold at 10% loss:
SP₂ = 0.90(4800 − x)
Total SP:
1.34x + 0.90(4800 − x) = 5442
✏️ Step 3: Solve equation
1.34x + 4320 − 0.90x = 5442
0.44x + 4320 = 5442
0.44x = 1122
x = 1122 / 0.44
x = 2550
✏️ Step 4: Find other CP
Second item CP = 4800 − 2550
= 2250
✏️ Step 5: Find Difference
Difference = 2550 − 2250
= ₹300
🎯 Correct Answer: B) ₹300
4)If the selling price of a bed is 2-times of initial, then the profit is 8-times of initial. Find the initial profit percentage(in %).
Let’s solve it clearly step-by-step.
🟢 Assume
Let initial cost price (CP) = ₹x
Let initial profit = ₹p
So,
Initial Selling Price (SP₁) = x + p
🟢 According to Question
New Selling Price (SP₂) = 2 × (initial SP)
= 2(x + p)
New Profit = 8 × (initial profit)
= 8p
But,
New Profit = SP₂ − CP
So,
2(x + p) − x = 8p
🟢 Solve the Equation
2x + 2p − x = 8p
x + 2p = 8p
x = 6p
So,
p = x / 6
🟢 Find Initial Profit %
Initial Profit % = (Profit / CP) × 100
= (x/6 ÷ x) × 100
= (1/6) × 100
= 16.67%
🎯 Correct Answer: D) 16.67%
Let’s solve it step by step.
🟢 Step 1: Let Cost Price (CP) = ₹x
Marked Price (MP) is 31% above CP
So,
MP = 1.31x
🟢 Step 2: Given MP = ₹744
1.31x = 744
x = 744 / 1.31
x = 568.70 (approx.)
So, CP = ₹568.70
🟢 Step 3: Profit is 9%
Selling Price (SP) = 1.09x
= 1.09 × 568.70
= ₹619.88 (approx.)
🟢 Step 4: Find Discount
Discount = MP − SP
= 744 − 619.88
= ₹124.12
🟢 Step 5: Discount %
Discount % = (Discount / MP) × 100
= (124.12 / 744) × 100
= 16.68% (approx.)
🎯 Final Answer: 16.68%
6)ಒಬ್ಬ ಮಾರಾಟಗಾರ 42 ಲ್ಯಾಪ್ಟಾಪ್ ಬ್ಯಾಗ್ಗಳನ್ನು ₹41,622 ಕ್ಕೆ ಖರೀದಿಸಿ 35 ಕ್ಕೆ ₹37,345 ಕ್ಕೆ ಮಾರಾಟ ಮಾಡುತ್ತಾನೆ. ₹3,952 ಲಾಭ ಗಳಿಸಲು ಎಷ್ಟು ಲ್ಯಾಪ್ಟಾಪ್ ಬ್ಯಾಗ್ಗಳನ್ನು ಖರೀದಿಸಿ ಮಾರಾಟ ಮಾಡಬೇಕು?
ಎ) 52
ಬಿ) 16
ಸಿ) 34
ಡಿ) 76
12/06/2025 ಶಿಫ್ಟ್-2
Let’s solve it step-by-step.
🟢 Step 1: Let Cost Price (CP) = ₹x
Marked Price (MP) is 34% above CP
So,
MP = 1.34x
Given MP = ₹578
1.34x = 578
x = 578 / 1.34
x = 431.34 (approx.)
So, CP ≈ ₹431.34
🟢 Step 2: Profit is 10%
Selling Price (SP) = 1.10x
= 1.10 × 431.34
= ₹474.47 (approx.)
🟢 Step 3: Find Discount
Discount = MP − SP
= 578 − 474.47
= ₹103.53
🟢 Step 4: Discount Percentage
Discount % = (Discount / MP) × 100
= (103.53 / 578) × 100
= 17.91% (approx.)
🎯 Final Answer: 17.91%
7)ಒಬ್ಬ ಡೀಲರ್ ಎರಡು ಡ್ರೈಯರ್ಗಳನ್ನು ಪ್ರತಿ ಡ್ರೈಯರ್ಗೆ ₹63,000 ದರದಲ್ಲಿ ಮಾರಾಟ ಮಾಡುತ್ತಾನೆ. ಒಂದರಲ್ಲಿ, ಅವನು 5% ಲಾಭ ಗಳಿಸುತ್ತಾನೆ ಮತ್ತು ಇನ್ನೊಂದರಲ್ಲಿ ಅವನು 30% ನಷ್ಟು ಕಳೆದುಕೊಳ್ಳುತ್ತಾನೆ. ಇಡೀ ವಹಿವಾಟಿನಲ್ಲಿ ಅವನ ನಷ್ಟದ ಶೇಕಡಾವಾರು ಎಷ್ಟು?
A dealer sells two dryers at the rate of ₹63,000 per dryer. On one, he earns a profit of 5% and on the other he loses 30%. What is his loss percentage in the whole transaction?
ಎ) 14%
ಬಿ) 17%
ಸಿ) 15%
ಡಿ) 16%
05/06/2025 ಶಿಫ್ಟ್-1
Let’s solve it carefully step-by-step.
🟢 Given:
Selling Price (SP) of each dryer = ₹63,000
On first dryer → 5% profit
On second dryer → 30% loss
✏️ Step 1: Find Cost Price of Each Dryer
🔹 First Dryer (5% Profit)
SP = 1.05 × CP
63000 = 1.05 × CP₁
CP₁ = 63000 / 1.05
CP₁ = ₹60,000
🔹 Second Dryer (30% Loss)
SP = 0.70 × CP
63000 = 0.70 × CP₂
CP₂ = 63000 / 0.70
CP₂ = ₹90,000
✏️ Step 2: Total Cost Price & Total Selling Price
Total CP = 60000 + 90000
= ₹1,50,000
Total SP = 63000 + 63000
= ₹1,26,000
✏️ Step 3: Net Loss
Loss = 150000 − 126000
= ₹24,000
✏️ Step 4: Loss Percentage
Loss % = (24000 / 150000) × 100
= 16%
🎯 Correct Answer: D) 16%
8)ತಯಾರಕರು 10% ಲಾಭ ಗಳಿಸಿದರೆ, ಸಗಟು ವ್ಯಾಪಾರಿ 15% ಮತ್ತು ಚಿಲ್ಲರೆ ವ್ಯಾಪಾರಿ 28% ಲಾಭ ಗಳಿಸಿದರೆ, ಗ್ರಾಹಕರ ಚಿಲ್ಲರೆ ಬೆಲೆ ₹75,900 ಆಗಿರುವ ಟೇಬಲ್ನ ಉತ್ಪಾದನಾ ವೆಚ್ಚವನ್ನು (₹ ನಲ್ಲಿ) ಕಂಡುಹಿಡಿಯಿರಿ. (ಗಮನಿಸಿ: ತಯಾರಕರು ಸಗಟು ವ್ಯಾಪಾರಿಗೆ ಮಾರಾಟ ಮಾಡುತ್ತಾರೆ, ಸಗಟು ವ್ಯಾಪಾರಿ ಚಿಲ್ಲರೆ ವ್ಯಾಪಾರಿಗೆ ಮಾರಾಟ ಮಾಡುತ್ತಾರೆ ಮತ್ತು ಚಿಲ್ಲರೆ ವ್ಯಾಪಾರಿ ಗ್ರಾಹಕರಿಗೆ ಮಾರಾಟ ಮಾಡುತ್ತಾರೆ.)
If the manufacturer gains 10%, the wholesaler gains 15%, and the retailer gains 28%, then find the cost of production of a table (in ₹), whose retail price for the customer is ₹75,900. (NOTE: Manufacturer sells to wholesaler, wholesaler sells to retailer and retailer sells to customers.)
ಎ) 60,000
ಬಿ) 53,906.25
ಸಿ) 46,875
ಡಿ) 51,562.5
16/06/2025 ಶಿಫ್ಟ್-3
Let’s solve it step by step (working backwards from retail price).
🟢 Given:
Retail Price (final price to customer) = ₹75,900
Profits:
Retailer = 28%
Wholesaler = 15%
Manufacturer = 10%
✏️ Step 1: Remove Retailer’s Profit (28%)
Retailer sells at 28% profit.
So,
Retail Price = 1.28 × Cost to Retailer
Cost to Retailer = 75900 / 1.28
= ₹59,296.875
✏️ Step 2: Remove Wholesaler’s Profit (15%)
Wholesaler sells at 15% profit.
Cost to Retailer = 1.15 × Cost to Wholesaler
Cost to Wholesaler = 59296.875 / 1.15
= ₹51,562.50
✏️ Step 3: Remove Manufacturer’s Profit (10%)
Manufacturer sells at 10% profit.
Cost to Wholesaler = 1.10 × Cost of Production
Cost of Production = 51562.50 / 1.10
= ₹46,875
🎯 Final Answer:
✅ Cost of Production = ₹46,875
9)A shopkeeper purchased 59 dozens of articles at the rate of ₹728 per dozen. He sold each one of them at the rate of ₹91. What percentage profit did he make?
A) 50%
B) 52%
C) 48%
D) 49%
14/06/2025 Shift-2
Let’s solve it step-by-step.
🟢 Step 1: Cost Price per article
Given:
Cost price per dozen = ₹728
1 dozen = 12 articles
So,
CP per article = 728 ÷ 12
= ₹60.67
🟢 Step 2: Selling Price per article
SP per article = ₹91
🟢 Step 3: Profit per article
Profit = 91 − 60.67
= ₹30.33
🟢 Step 4: Profit Percentage
Profit % = (Profit / CP) × 100
= (30.33 / 60.67) × 100
≈ 50%
🎯 Correct Answer: A) 50%
Let’s solve it step by step.
🟢 Step 1: Assume
Let original Cost Price (CP) = ₹x
He sold at 11% loss
So original Selling Price (SP₁):
SP₁ = 0.89x
🟢 Step 2: New Condition
If he had bought the item at 5% less,
New CP = 0.95x
He sold it for ₹739 more than before:
New SP = 0.89x + 739
And this time he would gain 20%
So,
New SP = 1.20 × (New CP)
🟢 Step 3: Form Equation
0.89x + 739 = 1.20 × 0.95x
0.89x + 739 = 1.14x
🟢 Step 4: Solve Equation
739 = 1.14x − 0.89x
739 = 0.25x
x = 739 / 0.25
x = 2956
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